好吧，比我想象的要容易。有一个alphahull选项，它要求自动计算相应的三角剖分。在from plotly.offline import iplot, init_notebook_mode

from plotly.graph_objs import Mesh3d

from numpy import sin, cos, pi

# some math: generate points on the surface of ellipsoid

phi = np.linspace(0, 2*pi)

theta = np.linspace(-pi/2, pi/2)

phi, theta=np.meshgrid(phi, theta)

x = cos(theta) * sin(phi) * 3

y = cos(theta) * cos(phi) * 2

z = sin(theta)

# to use with Jupyter notebook

init_notebook_mode()

iplot([Mesh3d({

'x': x.flatten(),

'y': y.flatten(),

'z': z.flatten(),

'alphahull': 0

})])

这是R版：

^{pr2}$

编辑：也可以使用type='surface'生成参数图：在这种情况下，必须提供二维x和{}。在library(plotly)

library(pracma)

mgrd

U

V

frame

plot_ly(frame, type='surface', x=x, y=y, z=z, showlegend=F, showscale=F,

colorscale=list(list(0, 'blue'), list(1, 'blue')))