Gem pooling、max pooling、average pooling
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gem时average pooling 的一般化
gem 的公式如下：
f(g)=[f1(g)...fk(g)...fK(g)]T=(1∣Xk∣∑xxpk)1pkf^{(g)} = [f_1^{(g)}...f_k^{(g)}...f_K^{(g)}]^T = (\frac{1}{|X_k|}\sum_xx^p{_k})^\frac{1}{p_k}f(g)=[f1(g)...fk(g)...fK(g)]T=(∣Xk∣1x∑xpk)pk1
当pk=1p_k=1pk=1时，gem pooling 退化为average pooling，即
f(a)=[f1(a)...fk(a)...fK(a)]T=1∣Xk∣∑xxf^{(a)} = [f_1^{(a)}...f_k^{(a)}...f_K^{(a)}]^T = \frac{1}{|X_k|}\sum_xxf(a)=[f1(a)...fk(a)...fK(a)]T=∣Xk∣1x∑x
当pk=∞p_k=\inftypk=∞时，gem pooling 退化为max pooling，即
f(m)=[f1(m)...fk(m)...fK(m)]T=maxxf^{(m)} = [f_1^{(m)}...f_k^{(m)}...f_K^{(m)}]^T = max xf(m)=[f1(m)...fk(m)...fK(m)]T=maxx
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